How to find Probability in this question? It gives different answer based on context.
Scenario 1:
Answer = 1
because we are getting Heads always. So probability of getting any number of Head such as be it 1, 2 , 3 or 4 it will be equal to 1.
Scenario 2 :
Answer = 0
because None of the times we got exactly 3 Head , so it should be 0.
I would say that this is conditional probability, although the wording is a bit strange. Usually we have wording like "given that" or "conditioned on" or "on the condition that". Your problem says: "and we get heads all the time" but to me this is acceptable way to state a condition.
If we assume that this is conditional probability then the answer is indeed 0.
$$ P(exactly\ three\ heads\ |\ all\ heads)=\frac{P((HHHT\ or\ HHTH\ or\ HTHH\ or\ THHH)\cap\ HHHH)}{P(HHHH)}=\frac{0}{P(HHHH)}=0 $$