If a series converges to zero, does this imply that the leading terms are zero? Or under what conditions would this be necessary?

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Suppose I have an infinite series, $$0= a_0 x^p + a_1 x^{p+1} + a_2 x^{p+2} + \mathcal{O}(x^{p+3})$$ where $x<1$ and $\mathbb{N}\ni p\geq 1$.


Under what conditions does it hold that $a_0=0$? In a proof, it was stated that $a_0=0$ because terms of order $\mathcal{O}(x^{p+1})$ cannot correct for this, otherwise i.e. $a_0 \neq 0$ would imply the series does not converge to $0$.

I don't immediately see why. Maybe it is not true in general, but under certain conditions?!

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The problem is oddly stated. Where is the infinite series? I see four terms added together. Nevertheless, we can show $a_0=0.$ On the interval $(-1,1)$ we are given

$$a_0x^{p}+a_1x^{p+1}+a_2x^{p+2} + O(x^{p+3})=0$$

(where you should say $O(x^{p+3})$ as $x\to 0$). Rewrite the above as

$$x^p(a_0+ a_1x+a_2x^{2} + O(x^{3}))=0.$$

For $x\ne0,$ we can divide by $x^p$ to get

$$a_0+ a_1x+a_2x^{2} + O(x^{3})=0.$$

Take the limit of this as $x\to 0.$ On the left we get $a_0.$ On the right we get $0.$ Therefore $a_0=0.$