I have following equation:
$$\frac{x-1}{e^x-1} = y$$
I want to solve this equation such that I have the value of $x$ in the term of $y.$ i.e. inverse of the equation
I have following equation:
$$\frac{x-1}{e^x-1} = y$$
I want to solve this equation such that I have the value of $x$ in the term of $y.$ i.e. inverse of the equation
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Hint. You may transform the equation $$ \frac{x-1}{e^x-1} = y \tag1 $$ with a little algebra into $$ -(x+y-1)e^{-(x+y-1)}=-ye^{1-y},\tag2 $$ set $X:=-(x+y-1)$ obtaining $$ Xe^X=-ye^{1-y} \tag3 $$ then use the Lambert function W to get