I'm learning perspective geometry and I have a question about the line at infinity. Is it true that if the conic has the line at infinity as its secant then the conic represents a hyperbola in Euclidean geometry?
If it is, how can I imagine the shape hyperbola using the line at infinity? I think I can lift up the line to infinity but it seems like a parabola than a hyperbola.
I draw a conic going through $A, B, C, D, E$, and I choose AB as the line at infinity. Then I lift it up and it seems like a parabola
P.S: I'm quite new to this field so I may use the wrong jargon. Thank you

I assume you are experimenting in Geogebra to get an intuition for this concept, and I'll answer from that point of view.
What you're currently doing is making $A,B$ approach the same point at infinity. As a result you are constructing a conic that meets the line at infinity at a single point, and thus has the line at infinity as a tangent, i.e. the conic is a parabola.
Instead, draw two lines $a,b$ intersecting at the origin, and then create a third line $c$. Let points $A,B$ be the intersections of $c$ with $a,b$. Then create a conic that goes through the points $A,B,C,D,E$ and move $c$ towards infinity. You'll tend towards a hyperbola. (It's more interesting if you choose $C,D,E$ so that your conic starts off as an ellipse.). Using this construction you'll ensure that $A,B$ approach different points at infinity, and you'll get a conic for which the line at infinity is a true secant.