In how many ways can five balls be chosen so that
(a) two are red and three are black?
(b) three are red and two are black?
out of $7$ black and $8$ red
Should I use permutation? or $8\times7\times7\times6\times5$?
And why?
2026-04-07 02:21:48.1775528508
In how many ways can five balls be chosen so that....
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You dont need to use permutation here because the ordering is not important .
You will have to choose combination here .
choosing $2$ red out of $8$ red = $_8C_2$ ways choosing $3$ black out of $7$ black = $_7C_3$ ways
therefore total number of ways of doing (a)= $_8C_2 * _7C_3$