Does $P(A|B,C) = P(A|C) => P(A,B) = P(A)*P(B)?$ And if so, how do I prove it?
I would intuitively say this is true since $P(A|B) = P(A)$ would mean $A$ and $B$ are independent and hence $P(A,B) = P(A)*P(B)$.
2026-04-24 16:53:23.1777049603
Independence/conditional probabilities
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