We can express linear transformations with their eigenvectors and eigenvalues in finite vector spaces if they are diagonalizable. even if they are not diagonalizable we can express them via Jordan normal form. So my question is basically if it's also valid in infinite function spaces? Can I express, for example, the operator $d/dx$ via its eigenfunction $f(x) = exp(x)$?
2026-04-06 16:11:17.1775491877
Infinite dimensional vector space eigenvectors eigenvalues and representation
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