The area of a triangle formed by the points $(p, 2-2p), (1-p, 2p)$ and $(-4-p, 6-2p)$ is 70. How many integral values of $p$ are possible?
I have been given these options:
- 2
- 3
- 4
- None of the above
I solved it using the shoelace formula, but is there a better (shorter or easier-to-understand) way than this?
Shift the origin to $(-p,-2p)$.
The vertices of the triangle in the new reference frame become :
$(2p,2)$, $(1,4p)$, and $(-4,6)$.
This will simplify your calculations.