I am searching for a sextic polynomial $f(x)$ that is irreducible over $\mathbb Q$ and factors in the following way over $\mathbb R$
$f(x)=((x+a)^2+d^2)((x+b)^2+d^2)((x+c)^2+d^2)$
where $d$ is a non-zero real number and $a,b,c$ are real numbers that are mutually distinct. Is this even possible?
Edit: Will Jagy just gave an example that is worth marking as answer. So now that we know that such polynomials over $\mathbb Q$ exists. Could we also prove that the splitting field of these polynomials, say $K$, will have a Galois group $Gal(K/\mathbb Q)$ that is never symmetric (or maybe could we even say that it is always cyclic?)
$$ x^6 - 3 x^4 + 2 x^3 + 12 x^2 - 12 x + 17 $$
You used + signs with a,b,c, so it comes out a little peculiar compared with how I built it: $$ a = 2 \cos \frac{7 \pi}{9} \; , \; \; b = 2 \cos \frac{5 \pi}{9} \; , \; \; c = 2 \cos \frac{ \pi}{9} \; , \; \; d=1 \; \; . $$
I started with the famous $z^3 - 3 z + 1.$ Because of the sign change, $a,b,c$ above are the roots of $w^3 - 3 w - 1 \; .$