Is $K^{n}$ Zariski Hausdorff when $K$ is a finite field?

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Assume that $K$ is a finite field. Is it true to say that $K^{n}$ is a Hausdorff topological space with Zariski topology?

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The Zariski topology on $K^n$ is discrete if $K$ is finite. If $K$ is any field, then for any point $p=(a_1,\dots,a_n)\in K^n$, $\{p\}$ is the vanishing set of the ideal $(x_1-a_1,\dots,x_n-a_n)$ and hence Zariski closed. If all singletons are closed, then all finite sets are closed, which means that all subsets of $K^n$ are closed if $K$ is finite.