I know that if you have $y=f(x+a)$, that shifts everything to the left by $a$ (which I tend to think of in terms that you are "tricking" the function by giving it an input that isn't actually $x$ but $x+a$. If you have $y=f(x)+a$, that shifts everything up by $a$ (because $y$ is equal to all of the outputs, $f(x)$, increased by the $+ a$).
What I find a bit confusing is whether or not $x+1$ would be more like the first, in the sense that you are modifying the input to an identity function, or the second where you are modifying the results of an identity function.
$$ \DeclareMathOperator{id}{id} y = x + 1 = \id(x+1) = \id(x) + 1 $$ The first case can be seen as $\id$ (the identity function) translated one unit to the left, the second as $\id$ translated one unit upwards. So both interpretations are fine.