On one side of an Angle A, the segments AB and AC are marked, and on the other side the segments AB' = AB and AC' = AC. Prove that the lines BC' and B'C meet on the bisector of A.
My confusion with this problem is the picture. I'm not certain whether AB' is a continuation of AB and whether AC' is a continuation of AC. If anyone could provide a picture that could help me solve this problem, I would appreciate it.
As it has been pointed out in the comments, I believe, those are distinct straight lines that intersect at $A$. Then, the picture that you are looking for looks something like the following: