Maximize the area of ​a triangle by differential

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Two sides of a triangle have lengths "a" and "b" and the angle between them is "θ". What value of "θ" will maximize the area of ​​the triangle? pd. sorry my bad english.

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The area of the triangle is $S=\frac{ab}{2}\sin\theta$. The maximum value for $\sin\theta$ is 1, then the angle that maximize the area is $\theta=\frac{\pi}{2}$ and the area will be $S_{max}=\frac{ab}{2}$.