Minimum steps to prove four points form a square.

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I have points $A, B, C, D$ and I need to show that $ABCD$ is a square. I tried this by showing all four sides have equal length and that two angles sharing a side are $90^{\circ}$ degrees. Is there a more concise way to prove the points form a square?

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Prove that $AC\perp BD$, $AC=BD$ and $AC$ and $BD$ have the same midpoint.