This is from Discrete Mathematics and its Applications

And the definition of strictly increasing.

Here is my work so far. 
I know that a direct proof involves making an assumption p, which in this case is that the function is strictly increasing, and then taking logical steps to reaching q, which is what I am trying to prove, in this case being -function is one to one.
I wrote down the assumption and am trying to take steps to get from that to the one to one definition. From intuition, I understand that if it's strictly increasing, no function outputs can be the same so there are no conditions broken for one to one. But what step should i take next in the direct proof to express this?
You are very nearly there. You just need to show that this function satisfies that definition.
So suppose that $f(x) = f(y)$ for some $x, y \in \mathbb{R}$. Then can we have $x \neq y$? Why/why not? Use the property that $x \neq y \implies f(x) \neq f(y)$ for this function!