Let $F$ be a field. By definition, the following are equivalent:
$F$ is algebraically closed.
Every nonconstant polynomial in $F[x]$ splits over $F$.
Every nonconstant polynomial in $F[x]$ has a root in $F$.
There is a subfield $K$, such that $F/K$ is algebraic and every nonconstant polynomial in $K[x]$ splits over $F$.
I want to know if the following condition also equivalent to the above:
(5) There is a subfield $K$, such that $F/K$ is algebraic and every nonconstant polynomial in $K[x]$ has a root in $F$?
If not, is there a counterexample?