This is the problem statement
An Indian farmer has a piece of farmland, say $L$ square kilometres long, and wants to either sow wheat or rice or a combination of both. The farmer has a limited amount of $F$ kg of fertilizer and $P$ kg of insecticides.
Every square kilometre of wheat requires $F1$ Kg of fertilizer and $P1$ Kg of insecticide. Every square kilometre of rice farming requires $F2$ Kg of fertilizer and $P2$ Kg of insecticide. Let $S1$ be the price obtained by selling wheat harvested from a square kilometre and $S2$ be the price obtained by selling rice harvested from a square kilometre.
You have to find the maximum total profit that the farmer can earn by selecting the area in which wheat and/or rice should be farmed.
For example:
$L = 10 Km^2 , F = 10 Kg, P = 5 Kg, F1 = 2 Kg, P1 = 2 Kg, F2 = 3 Kg, P2 > = 1 Kg, S1 = 14 , S2 = 25$.
In this case, the farmer will earn a maximum profit if he sows only Rice on $3.33 Km^2$ area and maximum profit value will be $83.33$.
Input Format
The only of input will consist of $9$ integers space-separated, $L, F, P, F1, P1, F2, P2, S1, S2$
Constraints
1 <= L <= 10^4
1 <= F <= 10^4
1 <= P <= 10^4
F1 + F2< = F
P1 + P2 <= P
1 <= S1 <= 10^4
1 <= S2 <= 10^4
Output Format
Output will be
- Maximum profit correct up-to 2 digits
- value in km 2 where wheat should be planted correct up-to 2 digits
- value in km 2 where rice should be planted correct up-to 2 digits . For the example considered in the question output will be $83.33$ $0.00$ $3.33$ .
Sample Test Case
Input
10 10 5 2 2 3 1 14 25
Output
83.33 0.00 3.33
Explanation
let us say that $L = 10 Km^2 , F = 10 Kg, P = 5 Kg, F1 = 2 Kg, P1 = 2 Kg, F2 = 3 Kg, P2 = 1 Kg, S1 = 14 , S2 = 25$ . Total profit will be maximum if farmer does not plant any wheat but plants rice on $3.33 Km^2$ area and maximum profit value is 83.33 .
I require a solution to this problem. However, unable to grasp the statement itself. Please help me.