Probabilities With Random Points in a Circle

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I'm currently doing some mathematical analysis of a system and I have distilled the problem down to a geometry/probability problem. I have a two part problem I would like to solve.

Part 1: Random Points on a Disk

From here, the probability density function of two points (randomly picked, uniformly) on a disk of radius $R$, having a distance between them of at most $s$ is:

$ f(s)=\frac{4s}{\pi R^2}\arccos\frac s{2R}-\frac{2s^2}{\pi R^3}\sqrt{1-\left(\frac s{2R}\right)^2}$

I'd like to adapt this to solve it for $n$ points. The question is this: Given $n$ points randomly distributed across a disk of radius, R, what is the probability that at least two of those points are within $s$ of each other?

My Guess: Take the integral of the above function from $0$ to $s$, and then multiply it by $^nC_2$ . However, this seems too simple. Am I mistaken?

Edit: As saulspatz below stated, this can't be right, because as $n$ increases, $\binom{n}{2}$ goes to $\infty$ , so I'm not sure how to solve this either.

Part 2: Total Expected Area of Overlap

Similar as above, but assume that the $n$ points selected all correspond to centers of circles with radius $r$. What is the expected area of overlap in terns of $n$, $R$ and $r$?

I did a bit of searching and there were a few topics that touched on this, but not really in the scope I was looking for:

Expected area of the intersection of two circles

Expected overlap of n circles of equal area randomly placed inside a circle of larger area

From what I could gather, this is a two part problem.

Part 2a: Area of Intersection of Two Circles

From here I found that the area of intersection of two circles with radii $r_1$ and $r_2$ at a distance $d$ from each other is as follows:

$A_{\textrm{intersection}} = r_1^2 \arccos\left(\frac{d_1}{r_1}\right) - d_1\sqrt{r_1^2 - d_1^2} \nonumber + r_2^2\arccos\left(\frac{d_2}{r_2}\right) - d_2\sqrt{r_2^2 - d_2^2}$

where:

$d_1 = \displaystyle\frac{r_1^2 - r_2^2 + d^2}{2d}$

and

$d_2 = d - d_1 = \displaystyle\frac{r_2^2 - r_1^2 + d^2}{2d}$

Because I'm only interested in circles of the same diameter, $r_1 = r_2 = r$ which can lead to some simplification of the equation above. I'll skip out on these simplifications for now.

Part 2b: Calculating Expected Areas

I'm not sure how to go about doing this here. After I simplify the above, clearly, I'm interested in looking at something $0 < d < 2r$ (if the distance between the two centers were more than $2r$, they would not intersect).

My Guess: I'd have to take some kind of integral of a function which is the product of the probability function $f(s)$ multiplied by the intersect area (setting $d=s$)

But those are only guesses from me. I'm not really sure if any of my guesses are correct (or even in the right direction). Could someone help?

Thank you

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You are unlikely to find a closed form expression for the probability of overlap and general $n$. Also, note that that for all $n$ sufficiently large there will be overlaps with probability $1$. Indeed, $n$ disjoint circles of radius $r$ will have a total area of $n\pi r^2$, which exceeds $\pi R^2$ whenever $n>(R/r)^2$.

It is likely that for your application, a sufficiently good approximation of the probabilities in question will be enough, in which case I refer you to the literature in the well-developed field of random spatial models where extremely similar problems are studied.