Probability in a non-symmetric binary channel

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My question is as follows:

In a nonsymmetric binary channel, $0$ and $1$ are transmitted independently in the proportion of $1:4$. If a $0$ was transmitted, we will receive $0$ with a probability of $0.9$. If a $1$ transmitted, we will receive $1$ with a probability of $0.95$.

a) What is the probability that a received symbol is "$1$"?

b) A "$1$" has been received what is the probability that a "$1$" actually been transmitted?

c) A "$0$" has been received what is the probability that a "$0$" actually been transmitted?

I found below answers but I am not sure:

a)

$P(R_1)=\frac{1}{5}*P(T_0|R_1)+ \frac{4}{5}*P(T_1|R_1)$=$\frac{1}{5}*0.1+ \frac{4}{5}*0.95=0.78$

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$(a)$ looks good

Hint for $(b)$

Use Bayes' Theroem:

$$\begin{align*} P(\text{1 transmitted | 1 received}) &=\frac{P(\text{1 transmitted} \cap 1\text{ received})}{P(\text{1 received})}\\\\ \end{align*}$$

where $P(\text{1 received})$ is what you solved correctly in part $(a)$

Hint for $(c)$

This calculation is similar noting that $$P(\text{0 received})=1-P(\text{1 received})$$