I am stuck with this question, I thought $(\frac{1}{2})^7$ but it is wrong. Any help would be much appreciated.
In a football game, the sides in the soccer field are determined on the
basis of a single coin flip by the referee and the team which correctly
guesses the flip result gets its desired side.
a) What is the probability that a team will have to wait until its 7th
game to get its desired side?
your result looks correct to me. It is a geometric distribution
$$\mathbb{P}[X=x]=(1-p)^{x-1}\cdot p=\left(\frac{1}{2}\right)^6\cdot\frac{1}{2}$$