Probability of $A$ given $A$ intersection $B$

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Two dice are rolled, and $A$ and $B$ stand for: $A=$ first of the numbers is an odd number, $B=$ the sum of the numbers is $4$.

How do I write down this probability?

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$P(A|A \cap B) = \frac{P(A \cap A \cap B)}{P(A \cap B)} = \frac{P(A \cap B)}{P(A \cap B)} = 1$