Choose two cards from a regular 52 card deck, what is the probability of getting atleast one face card from the two card hand drawn? (Without replacement) What is the probability that the first card from the two cards you get is a facecard? (fACE CARDS ARE K,Q AND J).
Part 2 What is the probability of getting atleast one face card in your hand of 2 choosen from 52.
On
Hint
What is the chance of not drawing a face card in the first draw? What is the probability of not drawing a face card in the second draw given that you did not draw a face card in the first draw? Call these $\lnot F_1$ and $\lnot F_2$, respectively. What does $1-(\lnot F_1)(\lnot F_2)$ represent?
HINT: how many face-cards are there in a deck?
HINT2: what is the probability of not drawing any face card for the two cards in you hand?
The first card has probability $\frac {40}{52}$ of not being a face card, the second one $\frac{39}{51}$. The probability of at least one face card is $1-\frac{40}{52}\frac{39}{51}$. (Why?)
There are $52$ cards in the deck, with $40$ non face cards. The probability of drawing a non face card is thus $\frac {40}{52}$. now, there are $39$ non-face cards left, out of $51$, so the probability of another non-face card is $\frac{39}{51}$. The probability of two non-face cards is: $\frac{40}{52}\frac{39}{52}$. Now, drawing no face cards is the opposite of at least one face cards, so we get $1-\frac{40}{52}\frac{39}{51}$.
Does the second card influence the probabilities for the first card?
No, once the first card is drawn, you know (can calculate the probability) whether it is a face card or not. The second card isn't important anymore.