Probability Question - Conditional Probability Staff

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80% of the company staff is male. 20% of the company staff is female.

57% of the staff's highest qualification is Ordinary Level. 32% of the staff's highest qualification is Advanced Level. Other's are graduates.

40% of the female staff's highest qualification is Ordinary Level. 45% of the female staff's highest qualification is Advanced Level. Other females are Graduates.

Now we choose a random person from the staff.

What I did

$80$ males + $20$ females

$40$ percent of $20$ females is $8$ OL females $45$ percent of $20$ females is $9$ AL females $15$ percent of $20$ females is $3$ Graduate females

Then $57-8$ = $49$ are up to OL males And $32-9$=$23$ are up to AL males. So $11-3$=$8$ are up to Graduate males.

  1. What is the probability of choosing a female whose highest qualification is Ordinary Level?

$$\frac{20}{100} \times \frac{40}{100} = \frac{8}{100}$$

  1. What is the probability of choosing a male whose highest qualification is Ordinary Level?

$$ \frac{49}{100}$$

  1. What is the probability of choosing a graduate, given that it is a male?

$$ \frac{8}{80}$$

4)What is the probability of choosing a female, given that it is a non-graduate staff member?

$$ \frac{\frac{17}{100}}{\frac{89}{100}}=\frac{17}{89}$$

Am I doing something wrong?

My book answers are not the same except for first question.