How can I prove this:
Let $G$ be a simple graph with with $n\geq3$ vertices and $m$ edges. If $m\geq \frac12 (n^2 - 3n +6),$ then $G$ has a Hamilton circuit.
How can I prove this:
Let $G$ be a simple graph with with $n\geq3$ vertices and $m$ edges. If $m\geq \frac12 (n^2 - 3n +6),$ then $G$ has a Hamilton circuit.
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