Prove that $\overrightarrow{AB}\cap \overrightarrow{BA} = \{A,B\}\cup \{X: A-X-B\}$

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As far as I can tell, both of these are perfectly sufficient definitions for a line segment $\overline{AB}$. The book I am using defines them the latter way, but is the first definition also equivalent?

If so how would I prove that these sets are in fact the same?

In other words how would I prove $$\overline{AB}:=\overrightarrow{AB}\cap \overrightarrow{BA} = \{A,B\}\cup \{X: A-X-B\}$$

EDIT: $A-X-B$ reads $X$ is between $A$ & $B$.

In other words, $A$, $B$, & $C$ are collinear and $\overrightarrow{XA}\cap \overrightarrow{XB} = \{X\}$

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According to my definitions

$\overrightarrow{AB}=\{A,B\}\cup\{X\colon A-X-B \vee A-B-X\}$ and $\overline{AB}=\{A,B\}\cup\{X\colon A-X-B\}$.

Hence the inclusion $\overline{AB}\subset\overrightarrow{AB}\cap\overrightarrow{BA}$ is obvious.

For the opposite inclusion you only need to know that

$P-Q-R \implies R-Q-P$ and $P-Q-R \implies \neg Q-P-R$,

in other words betweenness is symmetric and at most one of the three points is between the other two. Both these propertries are usually taken as axioms in axiomatic systems.