Is this proof correct? I know it can be proven using the Midpoint Theorem. I believe the proof is correct, in that case, please explain how I should prove it with the same approach without a graph. If it is incorrect, please explain why.
What I am basically trying to do involves interpreting:

(source)
on a graph such that CA is on the x-axis.
As point D lies in the centre of slope BA, y position for D should equal
(y position for B + y position for A)/2
=(y position for B)/2
y position for D = ED
y position for B = BC
Therefore, ED = 1/2 BC
Would appreciate if you could stick to layman terms.
EDIT1: Changed how I was expressing my doubt.
Alternative proof:
Since $\angle BAC = \angle DAE$ and ${BA\over DA} = {CA\over EA} =2$ triangles $ABC$ and $ADE$ are similar with ratio of similarity 2, so $BC = 2 DE$.