Proving that $\lfloor{X} \rfloor$ is a random variable

131 Views Asked by At

Let $X \sim$ Exp$(\lambda)$ and $Y:=\lfloor{X} \rfloor$.

How to prove that $Y$ is a random variable?

I used:

I want to show that $Y: \Omega \to \mathbb{R}$ is measurable.

Since $X \sim$ Exp$(\lambda)$, the cumulative distribution function is $F_X(x)=1-e^{-ay}$

I know that floor functions are monotone piecewise continuous functions.

So I wrote the floor function as

$$\sum_{n=-\infty}^\infty n \, \chi_{[n,n+1)}(x)$$

But how can I conclude that $Y$ is a random variable?