How do I prove that these probability functions are equal?
$$ P = \frac{e^{(a+bx)}}{1+e^{(a+bx)}}=\frac{1}{1+e^{-(a+bx)}} $$
How do I prove that these probability functions are equal?
$$ P = \frac{e^{(a+bx)}}{1+e^{(a+bx)}}=\frac{1}{1+e^{-(a+bx)}} $$
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Is this what you want? \begin{align*} P = \frac{e^{(a+bx)}}{1+e^{(a+bx)}} = \frac{e^{(a+bx)}}{e^{(a+bx)}(\frac{1}{e^{(a+bx)}}+1)} = \frac{1}{1+e^{-(a+bx)}} \end{align*}