I am having a hard time figuring out a problem. In a first price auction with a reserve price R and values of the bidders are U[0,1], how do we find expected revenue given the strategy of both of them is V/2. I am thinking of it like this if v < r or v = r revenue is zero. So what we are really looking at is scenarios where v>r for bidder 1 and v < r for bidder 2 (and vice versa) or we have a situation where we have both bidders v > r and so we'll have to take the max of that. Am I on the right track here? Why is this not bayes-nash equilibrium? I having been trying to figure this out forever. Help!
2026-04-02 01:20:19.1775092819
Questions about Auctions
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Regarding the strategy being a Bayesian-Nash equilibrium, my comment was misleading. I did not take into account the fact that you have a reservation price $R$. The strategy profile $(V/2,V/2)$ is a Bayesian-Nash equilibrium only for $R =0$.
To convince yourself that $(V/2,V/2)$ is not a Bayesian-Nash equilibrium for other values of $R$, consider the example $R = 1/4$. The strategy profile prescribes that players play $V/2$ whatever the actual realization of $V$. Now ask yourself whether this is really optimal when, for instance, $V$ happens to be $1/3$. In this case, does playing $1/6$ really maximizing your expected utility given that the value of the other bidder is distributed as a $U[0,1]$ and that you know that she will always play $V/2$? Once you get some intuition from this example, try to generalize it to any $R>0$.
As for the expected revenue, you do not need to bother about equilibrium considerations. You are being told that the agents play $(V/2,V/2)$, no matter that it be an equilibrium.
Now I realize my comment was maybe misleading again : the random variable I referred to was not $U[0,1]$ but the random variable you describe, namely the random variable which takes values
This is really the random variable you want to compute the expected value of.