We had a quiz given where we are supposed to pick out the incorrect answer. The options given are
If $X_1 , \dots, X_n $ is a random sample from a normal population with population mean 1 and variance 2, then $ 0.5 \left((X_1 - 1)^2 + \cdots + (X_n - 1)^2 \right)$ follows a chi-square distribution with degrees of freedom $n$.
If $T$ follows a t distribution with degrees of freedom $n$, then $T^2$ must follow an $F$ distribution
If $X_1 , \dots, X_n $ is a random sample from a normal population with population mean 0 and variance 1, then $\frac{\sqrt{n} \hat{X}}{S} $ must follow a t distribution, where $\hat{X}$ denotes the sample mean and $S$ denotes the sample standard deviation.
If $Y_1$ and $Y_2$ follow chi-square distributions with degrees of freedom $n_1$ and $n_2$ respectively, then $n_2 Y_1 / (n_1 Y_2)$ must follow an $F$ distribution
My chosen answer was the second option but apparently the correct answer is the last one. Can someone help me out with why???
In the last assertion note that there is no assumption that $Y_1$ and $Y_2$ are independent. Hence we cannot conclude the ratio will be $F$ distributed