Radius of convergence for power series of binomial expansion

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Now I know that there are other questions on the radius of convergence for the power series of binomial expansion, but they do not answer my question.

I already know that the binomial exapansion is expressed as $$(1+x)^r = \sum_{n=0}^r\binom{r}{n}x^n$$

And the power series I am talking about is $$ f(x) := \sum_{n=0}^\infty\binom{r}{n}x^n = 1 + rx + {{r(r-1)\over2}x^2} + \dots$$

I think that this can also be written as $ lim_{r\to\infty}(1+x)^r $. The radius of convergence of the power series above is well known as 1. However, if I substitute $x=1/2$ in $ lim_{r\to\infty}(1+x)^r $, the limit does not converge which contradicts the fact that the radius of convergence is 1. Can anyone explain to me what's going on here? Thanks.

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You seem to be confused. The generalized binomial expansion states that $$(1+x)^r=\sum_{n=0}^\infty\binom{r}{n}x^n$$ for $|x|\lt1$ where $r\in\mathbb{R}$. This also requires the definition $$\binom{r}{n}=\frac{r(r-1)\cdots(r-n+1)}{n!}$$ With this definition we have that $\binom{r}{n}$ is zero when $n\gt r$ and $r\in\mathbb{N}_0$ which causes the summation to simplify to $$(1+x)^r=\sum_{n=0}^r\binom{r}{n}x^n$$ when $r\in\mathbb{N}_0$.