If
$$ P(B|A)=\frac{P(A \cap B)}{P(A)} $$
then can the conditional probability be reversed ?
So that :
$$ P(A|B)=\frac{P(B \cap A)}{P(A)} $$
If
$$ P(B|A)=\frac{P(A \cap B)}{P(A)} $$
then can the conditional probability be reversed ?
So that :
$$ P(A|B)=\frac{P(B \cap A)}{P(A)} $$
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