Scaled distribution of Brownian motion

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If I have $X = 5(B_t - B_s)$

Does this have a distribution of $\sim \text{N}(0,25(t-s))$ ?

Since $B_t - B_s$ has distribution $\sim \text{N}(0,t-s)$

Then $X = \mu \cdot 0 + \sigma_1 Z$ where $Z \sim \text{N}(0,1)$ and $\sigma_1 = \sqrt{t-s}$

So $5X = \sigma_2 Z$ where $\sigma_2 = 5 \cdot \sigma_1$

so $5X \sim \text{N}(0, \sigma_2^2) = \sim \text{N}(0, 25(t-s))$

Would appreciate if someone could check this result and give it a thumbs up.