Show that the points $A(3;9), B(-2;-16)$ and $C(0.2;-5)$ lie on the same line.
We can say that three points lie on the same line if the largest segment bounded by two of these points is equal to the sum of the smaller ones. Can you show me why this is sufficient for three points to lie on the same line?
By the distance formula, we can get $AB=\sqrt{650}, BC=\sqrt{125.84}$ and $CA=\sqrt{203.84}$. How to check if $AB=BC+CA$?

If the points were not colinear, they would form a triangle. Using the triangle inequality, the sum of two smaller sides would always be greater than the biggest side, but in our case they are equal.
Write the distances as fractions:
$AB=\sqrt{650} ,\ BC=\frac{11}{5}\sqrt{26}, \ CA=\frac{14}{5}\sqrt{26}$
Now, $$BC+CA=5\sqrt{26} = \sqrt{25\times 26} =\sqrt{650}=AB$$ We’re done.