I currently have a problem with solving the following equation: $$0.75^x(x+3)\le0.3$$ It looks like it might be solvable using the Lambert-W function, but the x+3 throws me off. Wolframalpha is able to produce an exact result, so it should be solvable right?
2026-03-27 22:52:44.1774651964
Solve $\; 0.75^x(x+3)\le0.3 $ (Lambert-W-Function?)
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Multiply both sides with $0.75^3$, then solve for $x+3$ using Lambert's W function, and the fact that $a^b=e^{b\ln a}$ .