Solve for Y; don't understand Wolfram Alpha's solution

Question

Answering this StackOverflow question, I needed to solve this equation in terms of y:

$$x = 6.1 + \log(\frac{{y}}{{0.03p}})$$

Doing it by hand:

$$y = 0.03p10^{{(x-6.1)}}$$

Wolfram alpha tells me it's:

$$y = 3p10^{{(x-8.1)}}$$

How are these equivalent?

EDITS

So the how is pretty straightforward, but now the why. Is this a simpler form of the equation or an artifact of Wolfram's processing?

Answer 1

$y=3p10^{x-8.1}=3p10^{x-6.1-2}=3p10^{x-6.1} 10^{-2}=0.03p10^{x-6.1}$.