Given: $f(x) = \frac{4}{\sqrt{x-4}}$
Solve: $\frac{f(x) - f(20)}{x-20}$
My solution: $\frac{(4x-80)\sqrt{x-4} - (x-4)(x-20)}{x-4}$
However, it says I am incorrect. Please Help. Thanks.
Given: $f(x) = \frac{4}{\sqrt{x-4}}$
Solve: $\frac{f(x) - f(20)}{x-20}$
My solution: $\frac{(4x-80)\sqrt{x-4} - (x-4)(x-20)}{x-4}$
However, it says I am incorrect. Please Help. Thanks.
It's differentiation of $f(x)$ because $\frac{df}{dx}=\frac{f(a)-f(b)}{a-b}$.
We have $f(x)=\frac{4}{\sqrt{x-4}}$ $$\frac{df}{dx}=-\frac{2}{(x-4)\sqrt{(x-4)}}$$ put $x=20$ and get the answer.