Spherical Triangle

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I know that the area for a spherical triangle is calculated as Area $= r^2(a+b+c-\pi)=r^2E$ where $E= (a+b+c-\pi)$ is the spherical excess I was wondering why do you have to multiply by $r^2$ (the radius)?

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Areas of figures with the same shape are proportional to the squares of distances involved. Thus the area enclosed by a circle must be some constant times $r^2$. The area of a regular pentagon whose side has length $s$ must be some constant times $s^2$. And so on. The constant depends on the shape.