Disclaimer
This thread is meant to record. See: Answer own Question
Reference
It is a follow-up to: Uniform Spaces: Neighborhood System
It has relevance to: TVS: Uniform Structure
Problem
Given a topological space $\Omega$.
Consider inequivalent uniform structures: $\mathcal{U}\ncong\mathcal{U}'$
Can it happen that both induce the same topology: $\mathcal{U}^{(\prime)}\to\mathcal{T}$
Consider in particular TVS!
Yes it can happen!
Given the real line $\mathbb{R}$.
Consider the metrics $d(x,y):=|x-y|$ and $d(x,y):=|\arctan x-\arctan y|$.
So both give rise to the same topology.
But they cannot be equivalent as: $x_n:=n:\quad d(x_m,x_n)'\to0$
(Note how sublteties arise on the uniqueness of finite dimensional TVS.)
(Caution also that it reveals incompatibility with uniform structure of TVS.)