The angle of elevation of a tower, $CD$, from a point $A$ due East of the tower is 45°. From a point $B$ due south of $A$, the angle of elevation is 30°. The distance from $A$ and $B$ is 400 metres. Find the height, $h$, of the tower. Write your answer correct to three significant figures.
Thank you for any help!
Hint:
You have $CA=h$ and $CB=h\sqrt{3}$ and $CB^2=CA^2+AB^2$ so the equation:
$$ 3h^2=h^2+(400)^2 $$