Two persons $A, B$ roll a fair $n$-face dice separately and get $1 \le x,y \le n$ points. Then the third party will put $x + y$ dollars in a black box. $A$ and $B$ only know the point they roll and don't know the other's.
Then they bid on the black box. $A$ bids a integer price $p_1$, then $B$ can only bid at least $1$-dollar higher integer price $p_2$ or give up. If $B$ gives up, then $A$ must buy the black box with price $p_1$. If $B$ bids $p_2$, then $A$ can bid at least $1$-dollar higher integer price $p_3$ or give up, etc. Until one gives up, the other one should buy the black box with the latest price.
Question:
Assuming that $A$ and $B$ are rational, what's the optimal strategy of first player $A$ and second player $B$? How can, from the other one's bidding price, infer the range of points the other one has?
What if the other one should have to bid at least $k$ dollars higher ($k$ is integer)?
What if when there are $m$ players? (same question as Q1 and Q2).
Is there any terminology of this problem? Is there any reference or literature which thoroughly discusses this problem?
Assume strategies are known by the other player.
n=1. Always bid 1. You win 1 dollar or the other player bids 2 and no one wins.
n=2. When $x$ is rolled, the pot is $x+1$ or $x+2$, so bidding $x+1$ nets 0 or 1. Bidding 2 each time gives no information to player 2, so if player 2 rolls a 1, then player 2 is risking a loss by bidding 3, so player 2 will only bid 3 if they roll a 2. Thus bidding 2 each time will net a profit of 1 half the time (and 0 otherwise). The second strategy (bidding 2 every time) has the advantage that your opponent cannot cut you out of your profits by responding to a bid of 3 with 4. Though a bid of 4 may be considered irrational as it will never net a profit, as it is possible that your opponent's strategy may change. If you don't want your opponent to win money, bidding $x+1$ each time ensures he cannot profit. If you only care about your own winnings, then either strategy is suitable. Player 2 should always bid $y+1$. As you can see from this example, the problem is not specific enough to have a single answer, even in this very simple case. So the problem needs more specification around preferences, though more could be said in the instance where $k > 1$ .