Among the 30 applicants for a position at a bank, some are married and some are not, some have had experience in banking and some have not, with the exact breakdown being:
Married Single
Some experience 6 3
No experience 12 9
If the branch manager randomly chooses the applicant to be interviewed first, in which M denotes the event that the applicant is married, and E denotes that the applicant has had some experience in banking, find the value of $P(M)$, $P(M \cap E)$ and $P(E|M)$.
I answered it like this, but not really sure if it is correct:
$P(M) = 18/30 = 0.6$
$P(M \cap E) = 6/30 = 0.2$
$P(E|M) = P(E \cap M)/ P(M) = 0.2/0.6 = 0.33$