W.s.s. Gaussian process in LTI, probability of the output signal

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Let {${X(t); t\in ℝ}$} be a wide sense stationary Gaussian process with mean $\mu_X = 1$ and power spectral density $$S_X(f) = \begin{cases} 1, \ \text{if} \ |f| < 5; \\ 0, \ \text{otherwise}. \end{cases}$$

This process is the input of a LTI with impulse response $$h(t) = \begin{cases} 8e^{-4t}, \ \text{if} \ t >0; \\0,\ \ \ \ \ \ \ \text{otherwise}. \end{cases}$$

Let {${Y(t); t\in ℝ}$} be the output signal.

We must compute $P(Y(1)>1)$.

As {${X(t); t\in ℝ}$} is wide sense stationary, I know that we can compute its autocorrelation function as the inverse Fourier transform of its power spectral density $S_X(f)$. This gives us : $$ R_X(\tau) = sinc \ (\frac {5} {\pi} \tau)$$

Here is my question, I don't know how to make the link between this autocorrelation function and the probability that we want to compute. Should I compute the convolution $$ R_X(\tau) \ \ * \ \ h(1)$$

But then I don't how to use the given mean...

Or should I use the fact that the input signal {${X(t); t\in ℝ}$} is a Gaussian process to say that the output signal also is, and somehow compute the probability using this ?

Does anyone have an idea ? Thanks.