We choose 2 different people - what is the probability that they all have the same color of the eyes

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So I have big problems with the problem above... I tried for like 5 hours to find the solution but I just don't know how to proceed. So, there are 45 people, and 5 eye colors. Dark Brown = 20; Blue = 10; Green = 8 ; Light-Brown = 4; Black = 3

I did a tree diagram and I multiplied the values for each, for example: P(D.Brown)= $\frac{20}{45} \cdot \frac{19}{44} = 0.19$

After that, I don't know what to do..

edit: i forgot to mention that it says (draw without replacement)

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You're right so far, but like you said you need to do more. 20/45*19/44= 19/99 (dark brown eyes) 10/45*9/44= 1/22 (blue eyes) 8/45*7/44= 14/495 (green eyes) 4/45*3/45= 1/165 (light brown eyes) 3/45*2/45= 1/330 (black eyes) Now add all the answers up 19/99+1/22+14/495+1/165+1/330= 136/495 or in decimal form around 0.2747, or 27.5%