Weyl's law asymptotic order confusion

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Let $M$ be a compact Riemannian manifold of dimension $n$. Let $N(\lambda)$ be the number of eigenvalues of the Laplacian on $M$ which are less than or equal to $\lambda$. According to https://bookstore.ams.org/cbms-125/,
also
https://mathoverflow.net/questions/88784/weyls-law-on-asymptotic-of-laplacian-vs-hilberts-theorem-on-degree-of-a-projec
Weyl's law states that the function $N(\lambda)$ has asymptotic: $$N(\lambda) = C_n Vol(M) \lambda^n + O(\lambda^{n-1}),$$ for some explicit constant $C_n$ depending only on $n$. See, p. 3: enter image description here

But several other books and https://en.wikipedia.org/wiki/Minakshisundaram-Pleijel_zeta_function says $$N(\lambda )\sim {\frac {\omega _{n}Vol(M)\lambda ^{{n/2}}}{(2\pi )^{n}}}.$$ See also: How to obtain $N_{\mu, i} (\lambda)=c_n \text{vol} (Q_i) \lambda^{\frac{n}{2}}+o(\lambda^{\frac{n}{2}})$? - Weyl's law

It does not seem these are consistent to me. Am I missing something? Or did the author of the book above mean $N(\lambda):=\{j\mid \lambda_j\le \lambda^2\}$?

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In the book https://bookstore.ams.org/cbms-125/, $\lambda_j$'s are defined as eigenvalues of $\sqrt{-\Delta}$. The question https://mathoverflow.net/questions/88784/weyls-law-on-asymptotic-of-laplacian-vs-hilberts-theorem-on-degree-of-a-projec shoudl be a typo.

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