In chapter 13 (beginning of probability theory) of the book "challenge and thrill of pre college mathematics", after theorem 3 (i.e. for any 2 events E and F, P(E union F)=P(E)+P(F)+P(E intersection F)), there is an illustration in which "P(throwing either an even number or a sum of 2,3,4,with two dice)" has to be calculated.
The illustration is : E=event{2,4,6}, F=event{2,3, 4}. Then E U F={2,3,4,6},P(E U F) =11/36. P(E) =9/36, P(F) =6/36, P(EF) =P(2, 4) =4/36. P(E) +P(F) -P(EF) =(9+6-4) /36=11/36=P(E U F).
My questions are, 1.) what does it mean "to throw an even number on 2 dice"?(should the sum of 2 numbers on 2 dice be even?)
2.) "sum of 2,3,4" means all possible sums from 2,3,4(i.e. 2+3=5,3+3=6,3+4=7,4+4=8,3+3=2+3+4=9 etc.),or sum of numbers on the dice should be 2,3 or 4?
This is what your textbook means:
Let's throw 2 fair dice:
Event $E$: the sum of the "2 dice's face up" is even
Event $F$: the sum "2 dice's face up" is 2,3 or 4
Find
$$\mathbb{P}[E \cup F]=\mathbb{P}[E ]+\mathbb{P}[ F]-\mathbb{P}[E \cap F]=\frac{1}{2}+\frac{6}{36}-\frac{4}{36}=\frac{5}{9}$$