I'm trying to solve an interesting trig/optimisation problem that I've never seen before. Thought I'd reach out for inspiration.
I need to figure out a solution (value of x & y) to the below statment:
abs($sin(n* \pi* x) + sin (n*\pi*y)) =K$, where K is a constant for any odd integer value of n.
Solution must satisfy:
abs($sin(1* \pi* x) + sin (1*\pi*y)) =K$
abs($sin(3* \pi* x) + sin (3*\pi*y)) =K$
abs($sin(5* \pi* x) + sin (7*\pi*y)) =K$
If anyone has any ideas on where to start it would be much appreciated!
Ps. Once I've cracked this I will have to solve: abs($sin(n* \pi* x) + sin (n*\pi*y)) + sin (n*\pi*z)) =K'$