Why Distribution Function Being Singular Imply having $\infty$ Weight along Diagonal and 0 Elsewhere

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This is a followup question from the previous post, where the following multivariate distribution function is given by:

$$\exp(-\frac12 \vec x^T\Sigma^{-1}\vec x)$$

Now, it was mentioned in the comments that if the $\Sigma$ was singular, such as follows:

$$\begin{bmatrix} 1 & 1\\ 1 & 1 \end{bmatrix}$$

then the

"distribution function however will be singular, having infinite weight along the diagonal and zero weight everywhere else"

I want to mathematically see how this is the case? How the diagonal is infinite weight and how the off diagonal are all 0's