This is the alternate form of the summation formula: $$ \sum^{n}_{k=0} a(c)^k = \frac{ac^{n+1} - a}{c - 1} $$
so why is this wrong? $$ \sum^{n}_{k=0} (-\frac{1}{2})^k = \frac{(-\frac{1}{2})^{n+1} - 1}{(-\frac{1}{2}) - 1} $$
This is the alternate form of the summation formula: $$ \sum^{n}_{k=0} a(c)^k = \frac{ac^{n+1} - a}{c - 1} $$
so why is this wrong? $$ \sum^{n}_{k=0} (-\frac{1}{2})^k = \frac{(-\frac{1}{2})^{n+1} - 1}{(-\frac{1}{2}) - 1} $$
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This formula is correct for $c\ne 1$.
Fraction in RHS has no sense, when $c=1$ $\Bigl($undefined value like $\dfrac{0}{0}$$\Bigr)$.