if,
$$f(m) = -e^{-3m} \left({27m^3 + 18m^2 +6m \over 3m} \right)$$
and,
$$q(m) =-e^{-3m}\left({27m^4 +27m^3 + 18m^2+ 6m \over 81m}\right)$$
note that, here, $m \ge 0$.
How to write q as a function of f. That is in the form q(f(m)).
My try towards a solution is given below. I hope someone can help me. Thank you!
$$q(m) = -{27m^4 e^{-3m} \over 81m} - e^{-3m}\left( {27m^3+18m^2+6m \over 27 \times 3m} \right) $$ $$q = -{m^3 e^{-3m} \over 3} - {f(m) \over 27 }$$ I am stuck here. Can anyone help me?